Free Tool · EN 1994-1-1 §6.2 & §6.6 & §7.3

Composite Beam Calculator

A composite beam is a steel section bonded to a concrete slab with shear studs. The slab carries compression, the steel carries tension, and the studs lock the two together so they behave as a single unit. Enter your beam and slab details below. Get the design moment capacity, utilisation ratio, deflection, and how many studs you need — all backed by EN 1994-1-1. No sign-up, no PDF — just the numbers.

§6.2 Plastic moment §6.6.3 Stud resistance §7.3 Deflection §6.6.1 Degree of shear connection IPE · HEA · HEB C20/25 · C45/55

Steel Section

Concrete Slab

Design Loads (kN/m)

Shear Studs

Results EN 1994-1-1

Enter your beam and slab details and click
"Calculate" to get M_Rd, deflection and stud count.

The Math Behind It

Bending resistance (EN 1994-1-1 §6.2.1):

Fa = Aa · fyd (steel axial force)

Fc = beff · hc · (0.85·fckc) (slab force)

PNA found by force equilibrium; lever arm → Mpl,Rd

Stud resistance (EN 1994-1-1 §6.6.3 eq.6.18/6.19):

PRd1 = (0.8 · fu · π·d²/4) / γV   (shank)

PRd2 = (0.29 · α · d² · √(fck·Ecm)) / γV   (concrete)

α = 1.0 for hsc/d ≥ 4, else 0.2(hsc/d + 1)

PRd = min(PRd1, PRd2)  ·  γV = 1.25

Degree of shear connection (EN 1994-1-1 §6.6.1.2):

η = Nc / Nf   where Nf = Fa / PRd

Minimum η from Table 6.1 (e.g. η ≥ 0.4 for L ≤ 5 m, η ≥ 0.55 for L ≥ 15 m)

Deflection (EN 1994-1-1 §7.3.1):

Modular ratio n = Ea / Ecm (transformed section)

Short-term: Ecm = 22000 · ((fck+8)/10)0.3 MPa

Creep: nL = n · (1 + φt) where φt = 2.5 typically

Δ = (5/384) · q · L&sup4; / (E·I)   for simply-supported

IPE 400, L = 8 m, C30/37, t_slab = 120 mm, b_eff = 2000 mm

Reference result

IPE 400 · L = 8 m · C30/37 slab (f_ck = 30 MPa, E_cm = 32837 MPa) · t_slab = 120 mm · b_eff = 2000 mm · G = 5 kN/m, Q = 10 kN/m

M_Ed = (1.35·5 + 1.5·10) · 8² / 8 = (6.75 + 15) = 21.75 kNm design moment

A_a = 8450 mm² · f_yd = 355 MPa → F_a = 2999 kN

F_c = 2000 · 120 · 0.85·30/1.5 / 1000 = 4080 kN → steel governs PNA

M_pl,Rd = 505.8 kNm (PNA falls in top flange) · Δ = 2.8 mm (L/2857) · studs total (both spans) ≈ 74

Deep Dives

Common Questions

How does composite beam design work in Eurocode 4?
A composite beam combines a steel section with a concrete slab via headed studs welded to the top flange. The concrete carries compression, the steel carries tension, and the studs transfer horizontal shear at the interface. EN 1994-1-1 §6.2 gives the plastic moment resistance M_pl,Rd — the method used when the steel section is class 1 or 2 and the slab is in uniform compression.
What is the effective slab width b_eff?
EN 1994-1-1 §5.4.1.2 defines b_eff = b_0 + Σ b_ei where b_ei = min(L_e/8, b_i/2). For a simply-supported span, L_e = L. For an interior beam with slab on both sides, b_0 is the stud spacing across the web (typically 0) and b_1, b_2 are the distances from the beam centreline to the slab edges. A wider effective width increases the composite moment capacity.
How many shear studs do I need?
EN 1994-1-1 §6.6.1.2 requires N_f studs minimum where N_f = F_a / P_Rd and F_a = A_a · f_yd (steel section axial force). The degree of shear connection η = N_c / N_f must meet the minimum from §6.6.1.2 Table 6.1 (e.g. for simply supported spans: η ≥ 0.4 for L ≤ 5 m, η ≥ 0.55 for L ≥ 15 m — linear interpolation between). Full shear connection (η = 1.0) gives the maximum moment capacity.
What is the stud spacing requirement?
Studs must be spaced not more than 600 mm longitudinally along the beam. Transverse spacing must be at least 4d (or 5d for high-strength concrete) and not more than 2·h_sc. End studs must be within 300 mm of a concentrated load. For simply-supported beams with uniform loading, studs are typically distributed uniformly over the half-span adjacent to each support.
Why is deflection important for composite beams?
EN 1994-1-1 §7.3.1 checks SLS deflection, usually L/250 for beams and L/300 for cantilevers. The deflection of a composite beam depends on whether the slab is effective (wet stage vs long-term). At construction stage (steel only), use E_a and I_a. In service, use the modular ratio n = E_a / E_cm to transform the concrete to an equivalent steel area, giving the long-term transformed section properties.
IPE 400 composite beam — why ~480 kNm for a typical design?
IPE 400 (A = 8450 mm², f_yd = 355 MPa) gives F_a = 8450 × 355 / 1000 = 2999 kN. With a C30/37 slab (fck = 30 MPa, b_eff = 2000 mm, h_c = 120 mm) the full slab force F_c = 2000 × 120 × 0.85×30/1.5 / 1000 = 4080 kN, so the steel governs. PNA falls in the flange → M_pl,Rd ≈ 480 kNm. The exact value depends on where the PNA lands.
When can I use the plastic analysis method?
EN 1994-1-1 §6.2.1 allows plastic analysis for composite sections when the steel is class 1 or 2, the concrete is in uniform compression, and the shear connection satisfies §6.6.1. For class 3 steel sections, use elastic analysis (§6.4). For continuous beams with moment redistribution, class 1 or 2 is required.

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